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The following balanced equation shows the formation of water. 2H_(2)+O_(2)arrow 2H_(2)O How many moles of oxygen (O_(2)) are required to react completely with 1.67 mol H_(2) i 0.835molO_(2) 1.67molO_(2) 3.34molO_(2) 6.68molO_(2)

Question

The following balanced equation shows the formation of water.
2H_(2)+O_(2)arrow 2H_(2)O
How many moles of oxygen (O_(2)) are required to react completely with 1.67 mol H_(2) i
0.835molO_(2)
1.67molO_(2)
3.34molO_(2)
6.68molO_(2)

The following balanced equation shows the formation of water. 2H_(2)+O_(2)arrow 2H_(2)O How many moles of oxygen (O_(2)) are required to react completely with 1.67 mol H_(2) i 0.835molO_(2) 1.67molO_(2) 3.34molO_(2) 6.68molO_(2)

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ThaddeusMaster · Tutor for 5 years

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A

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The balanced chemical equation given is:\[2 \mathrm{H}_{2} + \mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2}\mathrm{O}\]This equation tells us that 2 moles of hydrogen gas (\(\mathrm{H}_{2}\)) react with 1 mole of oxygen gas (\(\mathrm{O}_{2}\)) to produce 2 moles of water (\(\mathrm{H}_{2}\mathrm{O}\)).To find out how many moles of \(\mathrm{O}_{2}\) are needed to react with \(1.67\) moles of \(\mathrm{H}_{2}\), we use the mole ratio from the balanced equation, which is \(2 \mathrm{H}_{2} : 1 \mathrm{O}_{2}\).So, for every 2 moles of \(\mathrm{H}_{2}\), we need 1 mole of \(\mathrm{O}_{2}\). If we have \(1.67\) moles of \(\mathrm{H}_{2}\), we need half of that amount in moles of \(\mathrm{O}_{2}\) because the ratio is 2:1.\[\text{Moles of } \mathrm{O}_{2} = \frac{1.67 \text{ moles of } \mathrm{H}_{2}}{2} = 0.835 \text{ moles of } \mathrm{O}_{2}\]Therefore, \(0.835\) moles of oxygen (\(\mathrm{O}_{2}\)) are required to react completely with \(1.67\) moles of hydrogen (\(\mathrm{H}_{2}\)).
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