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Look at the diagram showing the symbol equation for anaerobic respiration in yeast. Which number is missing? Enter your answer as a number C_(6)H_(12)O_(6)arrow ?C_(2)H_(5)OH+2CO_(2)

Question

Look at the diagram showing the symbol equation for anaerobic respiration in yeast.
Which number is missing?
Enter your answer as a number
C_(6)H_(12)O_(6)arrow ?C_(2)H_(5)OH+2CO_(2)

Look at the diagram showing the symbol equation for anaerobic respiration in yeast. Which number is missing? Enter your answer as a number C_(6)H_(12)O_(6)arrow ?C_(2)H_(5)OH+2CO_(2)

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ThomasAdvanced · Tutor for 1 years

Answer

The missing number is 2.

Explain

The equation given is for the anaerobic respiration (also known as fermentation) in yeast. The process of anaerobic respiration in yeast involves the breakdown of glucose (C6H12O6) into ethanol (C2H5OH) and carbon dioxide (CO2). <br /><br />In this process, one molecule of glucose (C6H12O6) is converted into two molecules of ethanol (C2H5OH) and two molecules of carbon dioxide (CO2). <br /><br />So, in the equation \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \rightarrow ? \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+2 \mathrm{CO}_{2}\), the missing number before \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) should be 2. <br /><br />This is because one glucose molecule gives two ethanol molecules in the process of anaerobic respiration in yeast.
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