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Drag and drop the correct answer choice to each answer blank. What are the x and y values in the solution to this system of equations? 3x+y=19 x-2y=4 Move the correct answer to each box. (3)/(4) x value: square y value: square

Question

Drag and drop the correct answer choice to each answer blank.
What are the x and y values in the solution to this system of equations?
3x+y=19
x-2y=4
Move the correct answer to each box.
(3)/(4)
x value: square 
y value: square

Drag and drop the correct answer choice to each answer blank. What are the x and y values in the solution to this system of equations? 3x+y=19 x-2y=4 Move the correct answer to each box. (3)/(4) x value: square y value: square

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Answer

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BetsyMaster · Tutor for 5 years

Answer

To solve for \(x\) and \(y\), we can use substitution or elimination. Here, we'll use substitution:First, rearrange the second equation to solve for \(x\):\(x = 2y + 4\)Then, substitute \(x\) in the first equation:\(3(2y + 4) + y = 19\)\(6y + 12 + y = 19\)\(7y = 7\)\(y = 1\)Substitute \(y = 1\) into the second equation to solve for \(x\):\(x = 2(1) + 4\)\(x = 6\)So, the solution to the system of equations is \(x = 6\) and \(y = 1\). Move the correct answer to each box.\(\mathrm{x}\) value: 6y value: 1
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