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3. MgCl_(2) is in solution while PbCh, is __ __ in solution while PbCl_(2) in solution. A. insoluble insoluble C. insoluble soluble B. soluble, soluble D. soluble , insoluble

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3. MgCl_(2) is in solution while PbCh, is __ __ in solution while PbCl_(2)
in solution.
A. insoluble insoluble
C. insoluble soluble
B. soluble, soluble
D. soluble , insoluble

3. MgCl_(2) is in solution while PbCh, is __ __ in solution while PbCl_(2) in solution. A. insoluble insoluble C. insoluble soluble B. soluble, soluble D. soluble , insoluble

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LawrenceElite · Tutor for 8 years

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D. soluble , insoluble

Explain

## Step 1: Understand the Problem<br />The problem is asking us to determine the solubility of \(MgCl_{2}\) and \(PbCl_{2}\) in solution. Solubility refers to the maximum amount of a substance that can be dissolved in a solvent at a given temperature. <br /><br />## Step 2: Recall the Solubility Rules<br />There are general rules of solubility that we can use to solve this problem. One of these rules states that all salts of alkali metals and ammonium ion are soluble. Another rule states that all chlorides, bromides, and iodides are soluble except those of silver, lead, and mercury.<br /><br />## Step 3: Apply the Solubility Rules<br />Based on these rules, \(MgCl_{2}\) is soluble because magnesium is an alkali metal and its chloride salt is soluble. On the other hand, \(PbCl_{2}\) is generally considered insoluble because lead chloride is an exception to the rule that all chlorides are soluble.
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