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MULTIPLE CHOICE QUESTION 1s^22s^22p^4 shows that __ has __ valence electrons Carbon 4 Oxygen 6

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MULTIPLE CHOICE QUESTION
1s^22s^22p^4 shows that __ has
__ valence electrons
Carbon
4
Oxygen
6

MULTIPLE CHOICE QUESTION 1s^22s^22p^4 shows that __ has __ valence electrons Carbon 4 Oxygen 6

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ZephyrElite · Tutor for 8 years

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Oxygen 6

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## Step1: <br />The given electron configuration is \(1s^{2}2s^{2}2p^{4}\). The number of valence electrons in an atom is determined by the total number of electrons in the outermost shell of the atom.<br /><br />## Step2: <br />From the given electron configuration, we can see that the outermost shell (n=2) has a total of 2 electrons from the \(2s^{2}\) orbital, and 4 electrons from the \(2p^{4}\) orbital.<br /><br />## Step3: <br />By adding the number of electrons in the \(2s^{2}\) and \(2p^{4}\) orbitals, we find the total number of valence electrons.<br /><br />### \(2s^{2} + 2p^{4} = 2 + 4 = 6\)
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