5. Cross a female who is colorblind with a man who has normal color vision. Tell the expected phenotypic ratio of their offspring. & & 6. Cross a female who is heterozygous for blood clotting factors with a man who has hemophilia. Tell the expected phenotypic ratio of the offspring. & & 7. Hairy ears are caused by a gene on the Y chromosome. If a male with hairy ears had children, what would be the expected phenotypes of his sons? His daughters? & & &

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5. Cross a female who is colorblind with a man who has normal color vision. Tell the expected phenotypic ratio of their offspring. & & 6. Cross a female who is heterozygous for blood clotting factors with a man who has hemophilia. Tell the expected phenotypic ratio of the offspring. & & 7. Hairy ears are caused by a gene on the Y chromosome. If a male with hairy ears had children, what would be the expected phenotypes of his sons? His daughters? & & &

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## Problem 5: For female offspring, 100% would have normal vision but be carriers of the colorblindness gene. For male offspring, 100% would be colorblind. ## Problem 6: For females, 50% will be heterozygous while 50% will have hemophilia. For males, 50% will be normal and 50% will have hemophilia. ## Problem 7: All sons will have hairy ears while none of the daughters will have hairy ears since it's a Y-linked trait.

Answer 2

## Step 1: The problem involves understanding the inheritance of X-linked traits and Y-linked traits. X-linked traits are those that are carried on the X chromosome, while Y-linked traits are carried on the Y chromosome. ## Step 2: ### **Problem 5** Colorblindness is an X-linked recessive trait. The male with normal vision has a genotype of X(R)Y, where (R) represents the normal vision allele. The female with color blindness has a genotype of X(r)X(r), where (r) represents the colorblindness allele. ## Step 3: When these two individuals reproduce, the female can pass on either X(R) or X(r), and the male can pass on either X(R) or Y. ## Step 4: ### **Problem 6** Hemophilia is an X-linked recessive disorder. The female who is heterozygous for blood clotting factors has a genotype of X(H)X(h), where (H) represents the normal allele and (h) represents the hemophilia allele. The male with hemophilia has a genotype of X(h)Y. ## Step 5: When these two individuals reproduce, the female can pass on either X(H) or X(h), and the male can pass on either X(h) or Y. ## Step 6: ### **Problem 7** Hairy ears are a Y-linked trait. Since only males have a Y chromosome, only men can have this trait. When a male with hairy ears has children, all sons will inherit the Y chromosome with the trait, while daughters will get their X chromosome from the father and will not have the trait.

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