When rolling a 10 -sided die, what is the probability of getting a number less than or equal to 5 or a number divisible by 3? (3)/(10) (3)/(5) (1)/(2) (7)/(10)

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When rolling a 10 -sided die, what is the probability of getting a number less than or equal to 5 or a number divisible by 3? (3)/(10) (3)/(5) (1)/(2) (7)/(10)

Answer 1

[]# By plugging the favorable number (7) and the total number of outcomes (10), the probability in this case is \( \frac {7}{10} \). Hence, the correct choice is \( \frac {7}{10} \).

Answer 2

## Step1: Analyze the conditions # In this problem, we are rolling a ten-sided die and would like to find the probability of either getting a number that is less than or equal to 5, OR a number that is divisible by 3. ## Step2: Count favorable outcomes # Numbers that are less than or equal to 5 on a 10-sided die are {1, 2, 3, 4, 5}, which is 5 numbers. Numbers that are divisible by 3 are {3, 6, 9}, which is 3 numbers. However, number 3 occurs in both conditions. So, the total number of distinct favorable numbers is 5 (for numbers less than or equal to 5) plus 2 (two remaining numbers divisible by 3 (i.e., 6 & 9) ) = 7. ## Step3: Determine the probability of an event occurring # Total possible outcomes on 10-sided die = 10. The definition of the probability of an event occurring can be given as: \noindent ### **Probability of an event = Number of favorable outcomes / Total number of possible outcomes **

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When rolling a 10 -sided die, what is the probability of getting a number less than or equal to 5 or a number divisible by 3? (3)/(10) (3)/(5) (1)/(2) (7)/(10)

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