Select the correct answer from each drop-down menu. Consider right triangle ABC. sin(A)=square v cos(A)=square =square square 40/41 9/41 40/9

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Select the correct answer from each drop-down menu. Consider right triangle ABC. sin(A)=square v cos(A)=square =square square 40/41 9/41 40/9

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To solve for the sine and cosine of angle A in right triangle ABC, we can use the definitions of sine and cosine in a right triangle:- Sine of an angle in a right triangle is the ratio of the length of the opposite side to the length of the hypotenuse.- Cosine of an angle in a right triangle is the ratio of the length of the adjacent side to the length of the hypotenuse.Given:- Triangle ABC is a right triangle with ∠B = 90°.- AC (the hypotenuse) = 41.- AB (adjacent to angle A) = 40.- BC (opposite to angle A) = 9.Step 1: Calculate sin(A)Using the definition of sine:\[\sin(A) = \frac{\text{opposite side to angle A}}{\text{hypotenuse}} = \frac{BC}{AC} = \frac{9}{41}\]Step 2: Calculate cos(A)Using the definition of cosine:\[\cos(A) = \frac{\text{adjacent side to angle A}}{\text{hypotenuse}} = \frac{AB}{AC} = \frac{40}{41}\]Answer:\[\sin(A) = \frac{9}{41} \quad \text{and} \quad \cos(A) = \frac{40}{41}\]

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Select the correct answer from each drop-down menu. Consider right triangle ABC. sin(A)=square v cos(A)=square =square square 40/41 9/41 40/9

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