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Find the volume of hydrogen gas that reacts with 200cm^3 of nitrogen gas measured at the same temperature and pressure. N_(2)(g)+3H_(2)(g)arrow 2NH_(3)(g) __ ..... iiiiii iiii ....iii iii .

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Find the volume of hydrogen gas that reacts with 200cm^3 of
nitrogen gas measured at the same temperature and pressure.
N_(2)(g)+3H_(2)(g)arrow 2NH_(3)(g)
__
.....
iiiiii iiii ....iii iii .

Find the volume of hydrogen gas that reacts with 200cm^3 of nitrogen gas measured at the same temperature and pressure. N_(2)(g)+3H_(2)(g)arrow 2NH_(3)(g) __ ..... iiiiii iiii ....iii iii .

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RosieProfessional · Tutor for 6 years

Answer

The volume of necessary hydrogen gas for the given conditions equals to \( 200~\mathrm{~cm}^{3} \times 3 \) equals \( 600~\mathrm{~cm}^{3} \).

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## Step1: Recognize the type of problem. <br />This problem is a stoichiometry problem in the field of chemistry. It is about determining the balanced equation for a given chemical reaction and calculating the volume of reactant gas when a certain volume of different gas is given. <br /><br />## Step2: Understand the given balanced equation. <br />The balanced chemical equation is given as: \( \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightarrow 2 \mathrm{NH}_{3}(g) \).<br />From this we understand that one volume of nitrogen gas reacts with three volumes of hydrogen gas to produce two volumes of ammonia gas. <br /><br />## Step3: Calculate necessary volume. <br />We are asked to find the volume of hydrogen gas that can react with \( 200 \mathrm{~cm}^{3} \) of nitrogen gas, at the same temperature and pressure. <br />According to the balanced reaction, one volume of nitrogen gas (N_{2}) reacts with three volumes of hydrogen gas (H_{2}). Therefore, to determine the volume of hydrogen gas, we multiply the volume of nitrogen gas by the ratio of the volumes of nitrogen to hydrogen in the reaction, which is 1:3.
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