A bag has blue (B)green(G) and yellow (M) cubes in it. There is at least one of each of the three colours. The teacher says: If you take a cube at random out of the bag. the probability that it will be green is (3)/(5) There are 20 cubes in the bag. What is the greatest number of yellow cubes there could be in the bag? square I

Question

Question

A bag has blue (B)green(G) and yellow (M) cubes in it. There is at least one of each of the three colours. The teacher says: If you take a cube at random out of the bag. the probability that it will be green is (3)/(5) There are 20 cubes in the bag. What is the greatest number of yellow cubes there could be in the bag? square I

Answer 1

Let's perform the calculations: ### \[ \text{Number of green cubes} = 20 \times \frac{3}{5} = 12 \] ### \[ \text{Maximum number of yellow cubes} = 20 - 12 - 2 = 6 \] So, the greatest number of yellow cubes there could be in the bag is 6.

Answer 2

## Step 1: First, we need to understand the problem. We know that the probability of picking a green cube is \( \frac{3}{5} \). This means that 3 out of every 5 cubes in the bag are green. ## Step 2: We also know that there are 20 cubes in the bag. To find out how many of these are green, we multiply the total number of cubes by the probability of picking a green cube. ### \[ \text{Number of green cubes} = \text{Total number of cubes} \times \text{Probability of green} \] ### \[ \text{Number of green cubes} = 20 \times \frac{3}{5} \] ## Step 3: Perform the multiplication to find the number of green cubes. ## Step 4: Since there is at least one cube of each color, we subtract the number of green cubes and 2 (one blue and one yellow) from the total number of cubes to find the maximum number of yellow cubes. ### \[ \text{Maximum number of yellow cubes} = \text{Total number of cubes} - \text{Number of green cubes} - 2 \]

Question

Answer

Answer

Explain

Hot Questions