In fact, Savio's average speed was greater than 40 miles per hour. (b) How does this affect your answer to part (a)'

you haven't provided the details of part (a), I am going to create a situation that sets up the problem like in the previous example.<br />Let's assume on the basis of the given information that part (a) asked the following question: "After qualifying from school, Kyle leaves school to travel to his home in New Jersey at an average speed of 40mph. 2.5 hours later, realizing that Kyle has his math homework, Savio drives on the same route at a slightly faster speed to give himself a chance to catch up with Kyle before he goes even farther. How far from school is Savio when he catches up with Kyle, if Kyle keeps a consistent speed?"<br /><br />Given, Savio travels with an average speed greater than 40mph, let's say it is 60mph. By the time Savio starts his journey, Kyle has already traveled = 2.5 hours * 40 mph = 100 miles. Initially, the speed difference between Savio and Kyle was 60mph - 40mph = 20mph. When Kyle and Savio both travel concurrently, Kyle's lead of 100 miles reduces to 20 mph.<br /><br />Therefore, it takes, for Savio, 100 miles/20 mph = 5 hours to catch up with Kyle. So, Savio would meet Kyle after 2.5 hours + 5 hours = 7.5 hours from when Kyle leaves the school. In this duration, Kyle moves at a steady speed of 40 mph, hence distance from the school when Savio catches up with him would be 7.5 hours * 40 mph = 300 miles.<br /><br />So, the increased speed of Savio compared to the example will mean that he "catches up with Kyle" farther out, because it takes him longer to make up the distance Kyle initially traveled. <br /><br />In conclusion, The point where Savio catches up with Kyle would be 300 miles from his school.【Answer】: 300