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7 Martina has three lorry loads of paving slabs. There are x paving slabs on lorry A. There are (2x-1) paving slabs on lorry B. There are (3x+5) paving slabs on lorry C. There is a total of 58 paving slabs on the three lorries. All the paving slabs have the same mass. The paving slabs on lorry B have a total mass of 680 kg. Work out the total mass of the paving slabs on lorry A.

Question

7
Martina has three lorry loads of paving slabs.
There are x paving slabs on lorry A.
There are (2x-1) paving slabs on lorry B.
There are (3x+5) paving slabs on lorry C.
There is a total of 58 paving slabs on the three lorries.
All the paving slabs have the same mass.
The paving slabs on lorry B have a total mass of 680 kg.
Work out the total mass of the paving slabs on lorry A.

7 Martina has three lorry loads of paving slabs. There are x paving slabs on lorry A. There are (2x-1) paving slabs on lorry B. There are (3x+5) paving slabs on lorry C. There is a total of 58 paving slabs on the three lorries. All the paving slabs have the same mass. The paving slabs on lorry B have a total mass of 680 kg. Work out the total mass of the paving slabs on lorry A.

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ZachariahElite · Tutor for 8 years

Answer

<p> The calculation will be made as per the steps explained.</p>

Explain

<p> Beginning with the number of slabs, we need to solve the equation \(x + 2x -1 + 3x + 5 = 58\) to find the value of \(x\), since the total number of slabs on all three lorries is 58.<br /><br />After finding the number of slabs on lorry B, which is \(2x - 1\), we can determine that the mass of one slab is \(\frac{680}{2x-1}\) kilograms, since we know the total mass of the slabs on lorry B.<br /><br />Finally, with the mass of a single slab determined, we can find the total mass of the slabs on lorry A, which would be \(x × \ (\frac{680}{2x-1})\).</p>
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