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If a red flower (EE) is cross bred with a yellow flower (ee), how many different phenotypes are possible?

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If a red flower (EE) is cross
bred with a yellow flower
(ee), how many different
phenotypes are possible?

If a red flower (EE) is cross bred with a yellow flower (ee), how many different phenotypes are possible?

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PerynAdvanced · Tutor for 1 years

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This question refers to a basic principle of Mendelian genetics concerning monohybrid crosses. A monohybrid cross involves a mating between two individuals with different alleles at one genetic locus of interest. The given alleles EE (for red flowers) and ee (for yellow flowers) suggest a simple dominance-recessive relationship.<br /><br />Here, the uppercase "E" denotes the dominant allele (for the red phenotype), and the lowercase "e" stands for the recessive allele (for the yellow phenotype). When individuals with these genotypes are crossed (EE x ee), all of their offspring will receive one allele from each parent. In this case, every offspring will have the genotype Ee, carrying both the dominant and recessive allele.<br /><br />As the dominant allele E is expressed over the recessive allele e, a parent passing on the E allele to its offspring would ensure that the offspring exhibit the red phenotype. Therefore, regardless of the fact that they have a heterozygous genotype (Ee), the phenotype will be red due to the presence of the dominant E allele.<br /><br />Since the question asks for the number of different phenotypes possible, we should only consider the observable traits, not the genotypes. The phenotypes are determined by the alleles that are expressed. In this case, since the E allele is always expressed over the e allele, there would only be one phenotype expressed (red) no matter the offspring's genotype being heterozygous (Ee).
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