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What volume of oxygen gas is needed to react with 4dm^3 of C_(3)H_(8)+5O_(2)arrow 3CO_(2)+4H_(2)O propane with complete combustion, with the volume of all gases measured at the same temperature and pressure? __

Question

What volume of oxygen gas is needed to react with 4dm^3 of C_(3)H_(8)+5O_(2)arrow 3CO_(2)+4H_(2)O
propane with complete combustion, with the volume of all gases
measured at the same temperature and pressure?
__

What volume of oxygen gas is needed to react with 4dm^3 of C_(3)H_(8)+5O_(2)arrow 3CO_(2)+4H_(2)O propane with complete combustion, with the volume of all gases measured at the same temperature and pressure? __

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JocastaExpert · Tutor for 3 years

Answer

### 20 \(\mathrm{dm}^{3}\)

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## Step 1: Identify the balanced chemical equation<br />### The balanced chemical equation is given as:<br />\[\mathrm{C}_{3} \mathrm{H}_{8} + 5 \mathrm{O}_{2} \rightarrow 3 \mathrm{CO}_{2} + 4 \mathrm{H}_{2} \mathrm{O}\]<br />This indicates the stoichiometric relationship between propane and oxygen.<br /><br />## Step 2: Determine the volume ratio from the balanced equation<br />### According to the balanced equation, 1 volume of propane (\(\mathrm{C}_{3} \mathrm{H}_{8}\)) reacts with 5 volumes of oxygen (\(\mathrm{O}_{2}\)).<br /><br />## Step 3: Calculate the required volume of oxygen<br />### Given that 4 \(\mathrm{dm}^{3}\) of propane is used, and using the volume ratio from the balanced equation:<br />\[\text{Volume of } \mathrm{O}_{2} = 4 \, \mathrm{dm}^{3} \times 5 = 20 \, \mathrm{dm}^{3}\]
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