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3. Which element would require the LEAST amount of energy to form a+1 ion? a. Sc b. Tỉ c. V d. Cr

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3. Which element would require the LEAST
amount of energy to form a+1 ion?
a. Sc
b. Tỉ
c. V
d. Cr

3. Which element would require the LEAST amount of energy to form a+1 ion? a. Sc b. Tỉ c. V d. Cr

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RowanProfessional · Tutor for 6 years

Answer

a. Sc

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The amount of energy required to form a positive ion from an atom, also known as ionization energy, is an indicator of how tightly an electron is held by an atom. The easier it is for an atom to lose its electron, the lower its ionization energy. An atom's ability to lose electrons, in turn, depends on its atomic structure, specifically the number of protons in its nucleus and the energy level of the electron to be lost.<br /><br />Looking at Scandium (Sc), Titanium (Ti), Vanadium (V), and Chromium (Cr), they all have positive charges as they lose one electron, forming $a+1$ ions. Among these elements, Scandium (Sc), is in Group 3 of the periodic table. Elements belonging to Group 3 lose electrons more efficiently because they hold their outermost electrons less tightly compared to elements in adjacent groups. Thus, less energy is required to remove these electrons.<br /><br />Titanium (Ti), Vanadium (V), and Chromium (Cr) belong to Groups 4, 5, and 6, respectively. As we move to greater atomic numbers within the same period in the periodic table, the hold on electrons becomes stronger, due to an increase in effective nuclear charge. Consequently, more energy is needed to remove an electron and form a positive ion.<br /><br />Considering these factors, the element that would require the least amount of energy to form $a+1$ ion would be Scandium (Sc). While the other elements also form $a+1$ ions, they require larger amounts of energy.
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