P=5^2times 18^2 Write P as a product of its prime factors. Give your answer in index form. P=Theta square

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Question

P=5^2times 18^2 Write P as a product of its prime factors. Give your answer in index form. P=Theta square

Answer 1

P = 2^2 * 3^4 * 5^2

Answer 2

The asked question is about prime factorization. To determine 'P' as a product of prime factors, we will first break down each number into prime factors and then write the product as a result. Step 1: Prime factorize 5 and 18. - 5 is a prime number its own only one prime factor is 5 itself. - Prime factors of 18 are 2 and 3, i.e., 18 = 2*3*3 Step 2: Write the prime factors of 'P'. - As '5^2 * 18^2', it discusses prime factors and squares that are occurring twice. - So, write two-times prime factors of '5' and '18'. - Write 'P' as product of prime factors in index form. Step 3: In index number form, base is the number written firstly and exponent is the frequency/number of occurrences in product, which would give us the final result.

Question

P=5^2times 18^2 Write P as a product of its prime factors. Give your answer in index form. P=Theta square

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