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/hich of the following numerical expressions gives the number of particles in 2.0 g of Ne? A (6.0times 10^23 particles /mol)/(2.0g) B (6.0times 10^23 particles /mol)/(20.18g/mol) C (2.0g)/(20,18g/mol)(6.0times 10^23 particles /mol) D (20.18g/mol)/(2.0g)(6.0times 10^23particles/mol)

Question

/hich of the following numerical expressions gives the number of particles in 2.0 g of Ne?
A (6.0times 10^23 particles /mol)/(2.0g)
B (6.0times 10^23 particles /mol)/(20.18g/mol)
C (2.0g)/(20,18g/mol)(6.0times 10^23 particles /mol)
D (20.18g/mol)/(2.0g)(6.0times 10^23particles/mol)

/hich of the following numerical expressions gives the number of particles in 2.0 g of Ne? A (6.0times 10^23 particles /mol)/(2.0g) B (6.0times 10^23 particles /mol)/(20.18g/mol) C (2.0g)/(20,18g/mol)(6.0times 10^23 particles /mol) D (20.18g/mol)/(2.0g)(6.0times 10^23particles/mol)

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KaiVeteran · Tutor for 9 years

Answer

C

Explain

<br />The task here is to find the number of particles (in this case atoms, as we're dealing with a monoatomic gas - Neon) in 2.0 g of Neon. To do this, we need to convert the amount from grams to moles and then to atoms.<br /><br />In each mole of any substance, be it atoms, molecules, electrons etc., there are approximately Avogadro's Number (~\(6.022 \times 10^{23}\)) of those particles. This is essential for counting particles at the atomic and molecular scale.<br /><br />Neon has an atomic mass of approximately 20.18 grams per mole. Knowing this, we can then address how to correctly convert from grams to moles and consequently to particle count.<br /><br />Option (A) simply divides Avogadro's number by the given mass. This is incorrect, as in a ratio of 'Particles to Moles' (Avogadro's number), there isn't a direct link to the deposited mass of the element. The atomic/molar mass must be included in the calculation. <br /><br />Option (B) effectively divides the available mass of Neon (2 g) by its molar mass (20.18 g/mol), converting grams to moles. However, Avogadro's number is divided by the molar mass - which is not directly linked to the particle count on its own, making this option incorrect.<br /><br />Option (D) also incorrectly frames how the molar mass/Avogadro's Number are used in this conversion, complicating the logic of how 'g' converts to 'mol' and then onto the particle count.<br /><br />But, in Option (C), the front ratio (2.0g / 20.18 g/mol) properly accounts for mass to molar conversion, providing the correct number of moles. The back term (Avogadro's Number per mol) hits the last conversion - from moles to particle count. As the '/' conventions divide down, everything constructs to provide an answer in the correct unit: atoms.
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