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0 2. 3 Calculate the percentage by mass of oxygen in lithium sulfate (Li_(2)SO_(4)) Relative atomic mass (A_(c)): O=16 Relative formula mass (M_(1)):Li_(2)SO_(4)=110 Give your answer to 2 significant figures. __ [4 marks] by mass of oxygen (2 significant figures)= 0 2].4 A solution of lithium sulfate contains 0.30 g of lithium sulfate in 25cm^3 4 Calculate the concentration of lithium sulfate in g/dm^3 __ [3 marks] Concentration=g/dm^3

Question

0 2. 3
Calculate the percentage by mass of oxygen in lithium sulfate (Li_(2)SO_(4))
Relative atomic mass (A_(c)): O=16
Relative formula mass (M_(1)):Li_(2)SO_(4)=110
Give your answer to 2 significant figures.
__
[4 marks]
by mass of oxygen
(2 significant figures)=
0 2].4
A solution of lithium sulfate contains 0.30 g of lithium sulfate in
25cm^3
4
Calculate the concentration of lithium sulfate in
g/dm^3
__
[3 marks]
Concentration=g/dm^3

0 2. 3 Calculate the percentage by mass of oxygen in lithium sulfate (Li_(2)SO_(4)) Relative atomic mass (A_(c)): O=16 Relative formula mass (M_(1)):Li_(2)SO_(4)=110 Give your answer to 2 significant figures. __ [4 marks] by mass of oxygen (2 significant figures)= 0 2].4 A solution of lithium sulfate contains 0.30 g of lithium sulfate in 25cm^3 4 Calculate the concentration of lithium sulfate in g/dm^3 __ [3 marks] Concentration=g/dm^3

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YvesProfessional · Tutor for 6 years

Answer

The percentage by mass of oxygen in lithium sulfate is approximately \( 58.18\% \) (rounded to 2 significant figures).<br /><br />The concentration of lithium sulfate in the solution is \( 12 \, \mathrm{g} / \mathrm{dm}^{3} \).

Explain

## Step 1: Calculate the percentage by mass of oxygen in lithium sulfate<br />Lithium sulfate (\( \mathrm{Li}_{2} \mathrm{SO}_{4} \)) consists of 2 lithium atoms, 1 sulfur atom, and 4 oxygen atoms. The atomic mass of oxygen is given as 16. The relative formula mass of lithium sulfate is given as 110. <br /><br />### The formula to calculate the percentage by mass of oxygen is: <br />### \( \frac{{\text{{mass of O}} \times \text{{number of atoms O}}}}{{\text{{molecular weight of lithium sulfate}}}} \times 100\% \)<br /><br />Substituting the given values into the formula, we get:<br /><br />### \( \frac{{16 \times 4}}{{110}} \times 100\% \)<br /><br />## Step 2: Calculate the concentration of lithium sulfate in \( \mathrm{g} / \mathrm{dm}^{3} \)<br />A solution of lithium sulfate contains 0.30 g of lithium sulfate in 25 cm³. <br /><br />### The formula to calculate the concentration is: <br />### \( \frac{{\text{{mass of solute}}}}{{\text{{volume of solution}}}} \)<br /><br />Note that the volume of the solution needs to be converted from cm³ to dm³. 1 dm³ = 1000 cm³. So, 25 cm³ = 0.025 dm³.<br /><br />Substituting the given values into the formula, we get:<br /><br />### \( \frac{{0.30}}{{0.025}} \)
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