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The diagram shows an isosceles triangle ABD and the straight line ABC. x:y=3:2 Work out the value of w.

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The diagram shows an isosceles triangle ABD and the straight line ABC.
x:y=3:2
Work out the value of w.

The diagram shows an isosceles triangle ABD and the straight line ABC. x:y=3:2 Work out the value of w.

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KylaMaster · Tutor for 5 years

Answer

Solving for \( w \) in the equation \( 5w = 180^\circ \) gives us \( w = \frac{180}{5} = 36^\circ \).

Explain

## Step 1:<br />In the given problem, we have an isosceles triangle \( A B D \) and a straight line \( A B C \). In an isosceles triangle, the base angles are equal. Therefore, we have \( \angle BAD = \angle BDA \).<br /><br />## Step 2:<br />The problem also mentions that \( x : y = 3 : 2 \). This means that the angle \( x \) is divided into 3 equal parts and the angle \( y \) is divided into 2 equal parts.<br /><br />## Step 3:<br />Since the straight line \( ABC \) forms a linear pair with \( \angle BAD \) and \( \angle BDA \), we know that the sum of these angles is \( 180^\circ \). Therefore, we have \( x + y = 180^\circ \).<br /><br />## Step 4:<br />Substituting the ratio of \( x : y = 3 : 2 \) into the equation, we get \( 3w + 2w = 180^\circ \), where \( w \) is the common ratio.<br /><br />### Step 5:<br />Solving the equation \( 5w = 180^\circ \) gives us the value of \( w \).
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