The drama club is selling tickets to their play. Tickets cost 12 for students and 20 for adults. The club sold 150 tickets and made 2,040. The graph models the situation. How many student and adult tickets were sold? A. They sold 30 student and 120 adult tickets. B. They sold 120 student and 30 adult tickets. C. They sold 100 student and 50 adult tickets. D. They sold 50 student and 100 adult tickets.

To solve this problem, we can set up a system of equations based on the information given. Let's denote the number of student tickets sold as \(s\) and the number of adult tickets sold as \(a\).We have two pieces of information:1. The total number of tickets sold is 150.2. The total amount of money made from selling the tickets is \(\$ 2,040\).From the first piece of information, we can write the equation:\[s + a = 150\] (Equation 1)From the second piece of information, we know that student tickets cost \(\$ 12\) each and adult tickets cost \(\$ 20\) each. So, the total money made can be represented by the equation:\[12s + 20a = 2040\] (Equation 2)Now, we can solve this system of equations. First, let's solve Equation 1 for one of the variables. We can solve for \(s\):\[s = 150 - a\] (Equation 3)Next, we substitute Equation 3 into Equation 2 to solve for \(a\):\[12(150 - a) + 20a = 2040\]\[1800 - 12a + 20a = 2040\]\[8a = 2040 - 1800\]\[8a = 240\]\[a = 240 / 8\]\[a = 30\]Now that we have the value for \(a\), we can substitute it back into Equation 3 to find \(s\):\[s = 150 - a\]\[s = 150 - 30\]\[s = 120\]Therefore, the drama club sold 120 student tickets and 30 adult tickets. The correct answer is:B. They sold 120 student and 30 adult tickets.