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How many grams of sodium sulfate must be added to make 500. mL of a 0 .25 M sodium sulfate solution? a 35.5g b 26.6g c 17.8g d 44.4g e 8.88 g

Question

How many grams of sodium sulfate must be added to make 500.
mL of a 0 .25 M sodium sulfate solution?
a 35.5g
b 26.6g
c 17.8g
d 44.4g
e 8.88 g

How many grams of sodium sulfate must be added to make 500. mL of a 0 .25 M sodium sulfate solution? a 35.5g b 26.6g c 17.8g d 44.4g e 8.88 g

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ConstanceElite · Tutor for 8 years

Answer

### C. 17.8 g

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## Step1: Calculate moles of sodium sulfate needed<br />### Use the formula: moles = molarity × volume (in liters). Here, $0.25\:M \times 0.5\:L = 0.125\:moles$.<br />## Step2: Determine the molar mass of sodium sulfate<br />### The molar mass of sodium sulfate (\(Na_2SO_4\)) is determined by adding the atomic masses of 2 sodium atoms, 1 sulfur atom, and 4 oxygen atoms. This is $(2 \times 23.0) + 32.1 + (4 \times 16.0) = 142.1\: g/mol$.<br />## Step3: Calculate the grams of sodium sulfate required<br />### Multiply the moles needed by the molar mass: $0.125\:moles \times 142.1\:g/mole = 17.7625\:g$, rounding to significant figures gives $17.8\:g$.
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