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A container is filled with mathrm(H)_(2) , and mathrm(H)_(2) mathrm(O) . Calculate the partial pressure of mathrm(H)_(2) when the pressure of water is 17torr. The tot pressure of the gases is 750 torr. 42.86torr 733torr 767.5torr

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A container is filled with mathrm(H)_(2) , and mathrm(H)_(2) mathrm(O) . Calculate the partial pressure of mathrm(H)_(2) when the pressure of water is 17torr. The tot pressure of the gases is 750 torr.
42.86torr
733torr
767.5torr

A container is filled with mathrm(H)_(2) , and mathrm(H)_(2) mathrm(O) . Calculate the partial pressure of mathrm(H)_(2) when the pressure of water is 17torr. The tot pressure of the gases is 750 torr. 42.86torr 733torr 767.5torr

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PatsyProfessional · Tutor for 6 years

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# Explanation<br />To calculate the partial pressure of \( \mathrm{H}_{2} \) in the container, we can use Dalton's Law of Partial Pressures. This law states that in a mixture of non-reacting gases, the total pressure exerted by the mixture is equal to the sum of the partial pressures of individual gases.<br /><br />Let \( P_{\mathrm{H}_{2}} \) be the partial pressure of hydrogen (\( \mathrm{H}_{2} \)) and \( P_{\mathrm{H}_{2}O} \) be the partial pressure of water (\( \mathrm{H}_{2}O \)). According to the problem, \( P_{\mathrm{H}_{2}O} = 17 \) torr and the total pressure \( P_{\text{total}} = 750 \) torr.<br /><br />Using Dalton's Law, we have:<br />\[ P_{\text{total}} = P_{\mathrm{H}_{2}} + P_{\mathrm{H}_{2}O} \]<br /><br />We can solve for \( P_{\mathrm{H}_{2}} \) by subtracting \( P_{\mathrm{H}_{2}O} \) from \( P_{\text{total}} \):<br />\[ P_{\mathrm{H}_{2}} = P_{\text{total}} - P_{\mathrm{H}_{2}O} \]<br />\[ P_{\mathrm{H}_{2}} = 750 \, \text{torr} - 17 \, \text{torr} \]<br />\[ P_{\mathrm{H}_{2}} = 733 \, \text{torr} \]<br /><br /># Answer<br />733torr
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