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New Question What is the RELATIVE FORMULA MASS (R.F.M) of O_(2)(O=16) R.F.M.M=average of all elements=(16)/(2)=8 R.F.M.a=average of all elements= ((16times 2))/(2)=16 R.F.M.M=sum of all elements=16 R.F.M.M=sum of all elements=16times 2=

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What is the RELATIVE FORMULA MASS (R.F.M) of O_(2)(O=16)
R.F.M.M=average of all elements=(16)/(2)=8
R.F.M.a=average of all elements=
((16times 2))/(2)=16
R.F.M.M=sum of all elements=16
R.F.M.M=sum of all elements=16times 2=

New Question What is the RELATIVE FORMULA MASS (R.F.M) of O_(2)(O=16) R.F.M.M=average of all elements=(16)/(2)=8 R.F.M.a=average of all elements= ((16times 2))/(2)=16 R.F.M.M=sum of all elements=16 R.F.M.M=sum of all elements=16times 2=

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OwenMaster · Tutor for 5 years

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The relative formula mass (R.F.M) of \(\mathrm{O}_{2}\) is 32.

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## Step 1:<br />To find the relative formula mass (R.F.M) of \(\mathrm{O}_{2}\), we need to sum the atomic masses of all the oxygen atoms in the molecule.<br /><br />## Step 2:<br />The atomic mass of one oxygen atom (O) is given as 16.<br /><br />## Step 3:<br />Since \(\mathrm{O}_{2}\) consists of two oxygen atoms, we multiply the atomic mass of oxygen by 2.<br /><br />### \(\text{R.F.M} = 16 \times 2\)<br /><br />## Step 4:<br />Perform the multiplication to find the R.F.M.<br /><br />### \(\text{R.F.M} = 32\)<br /><br />#
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