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Plutonium-238 undergoes alpha decay as shown: (}_{94)^238Puarrow _(Z)^AX+_(2)^4He Enter the appropriate values for A and Z and the chemical symbol for X. A: square z: square x: square

Question

Plutonium-238 undergoes alpha decay as shown:
(}_{94)^238Puarrow _(Z)^AX+_(2)^4He
Enter the appropriate values for A and Z and the chemical symbol
for X.
A: square 
z: square 
x: square

Plutonium-238 undergoes alpha decay as shown: (}_{94)^238Puarrow _(Z)^AX+_(2)^4He Enter the appropriate values for A and Z and the chemical symbol for X. A: square z: square x: square

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Answer

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FranklinElite · Tutor for 8 years

Answer

A: \( 234 \) <br />Z: \( 92 \) <br />X: \( \mathrm{U} \)

Explain

In alpha decay, an alpha particle (which is a helium nucleus, \({ }_{2}^{4} \mathrm{He}\)) is emitted. This reduces the mass number \( A \) by 4 and the atomic number \( Z \) by 2. Therefore, the new element \( X \) will have \( A = 238 - 4 \) and \( Z = 94 - 2 \).
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