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When 20 grams of KNO_(3) is dissolved in 100 grams of water at 80^circ C the solution can be correctly described as:

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When 20 grams of KNO_(3) is dissolved in 100 grams of
water at 80^circ C the solution can be correctly
described as:

When 20 grams of KNO_(3) is dissolved in 100 grams of water at 80^circ C the solution can be correctly described as:

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WesleyExpert · Tutor for 3 years

Answer

### The solution is unsaturated.

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## Step1: Identify the solute and solvent<br />### The solute is \( \mathrm{KNO}_{3} \) and the solvent is water (H$_2$O).<br /><br />## Step2: Determine the amount of solute and solvent<br />### There are 20 grams of \( \mathrm{KNO}_{3} \) dissolved in 100 grams of water.<br /><br />## Step3: Determine saturation level at the given temperature<br />### Check the solubility of \( \mathrm{KNO}_{3} \) at \( 80^{\circ} \mathrm{C} \). The solubility of \( \mathrm{KNO}_{3} \) at \( 80^{\circ} \mathrm{C} \) is approximately 168 grams per 100 grams of water.<br /><br />## Step4: Compare the provided solute amount with the solubility data<br />### Since 20 grams is much less than the 168 grams that can dissolve at \( 80^{\circ} \mathrm{C} \), the solution is not saturated.
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