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35. Which of the following reactions correctly shows the combustion of methane (CH_(4)) a. CH_(4)+2O_(2)arrow CO_(2)+2H_(2)O C CH_(4)+CO_(2)arrow O_(2)+H_(2)O b 2CH_(4)+2O_(2)arrow 2CO_(2)+2H_(2)O d. CH_(4)+2CO_(2)arrow 2O_(2)+2H_(2)O

Question

35. Which of the following reactions correctly shows the combustion of methane
(CH_(4))
a. CH_(4)+2O_(2)arrow CO_(2)+2H_(2)O
C CH_(4)+CO_(2)arrow O_(2)+H_(2)O
b 2CH_(4)+2O_(2)arrow 2CO_(2)+2H_(2)O
d. CH_(4)+2CO_(2)arrow 2O_(2)+2H_(2)O

35. Which of the following reactions correctly shows the combustion of methane (CH_(4)) a. CH_(4)+2O_(2)arrow CO_(2)+2H_(2)O C CH_(4)+CO_(2)arrow O_(2)+H_(2)O b 2CH_(4)+2O_(2)arrow 2CO_(2)+2H_(2)O d. CH_(4)+2CO_(2)arrow 2O_(2)+2H_(2)O

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MerylElite · Tutor for 8 years

Answer

a. \(\mathrm{CH}_4 + 2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2 + 2 \mathrm{H}_2\mathrm{O}\)

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Combustion reactions typically involve a hydrocarbon reacting with oxygen (\(\mathrm{O}_2\)) to produce carbon dioxide (\(\mathrm{CO}_2\)) and water (\(\mathrm{H}_2\mathrm{O}\)). In this case, methane (\(\mathrm{CH}_4\)) is the hydrocarbon.<br /><br />The general form of a combustion reaction for a hydrocarbon is:<br />\[\text{Hydrocarbon} + \mathrm{O}_2 \rightarrow \mathrm{CO}_2 + \mathrm{H}_2\mathrm{O}\]<br /><br />For methane (\(\mathrm{CH}_4\)), the balanced chemical equation for its combustion is:<br />\[\mathrm{CH}_4 + 2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2 + 2 \mathrm{H}_2\mathrm{O}\]<br /><br />Let's examine the given options:<br /><br />- Option a: \(\mathrm{CH}_4 + 2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2 + 2 \mathrm{H}_2\mathrm{O}\)<br /> - This matches the balanced equation for the combustion of methane.<br /><br />- Option b: \(2 \mathrm{CH}_4 + 2 \mathrm{O}_2 \rightarrow 2 \mathrm{CO}_2 + 2 \mathrm{H}_2\mathrm{O}\)<br /> - This equation is not balanced correctly. The correct balanced form would involve 4 \(\mathrm{O}_2\) molecules on the reactant side.<br /><br />- Option c: \(\mathrm{CH}_4 + \mathrm{CO}_2 \rightarrow \mathrm{O}_2 + \mathrm{H}_2\mathrm{O}\)<br /> - This does not represent a combustion reaction, as \(\mathrm{CO}_2\) is not a reactant in combustion.<br /><br />- Option d: \(\mathrm{CH}_4 + 2 \mathrm{CO}_2 \rightarrow 2 \mathrm{O}_2 + 2 \mathrm{H}_2\mathrm{O}\)<br /> - This also does not represent a combustion reaction, as \(\mathrm{CO}_2\) is not a reactant in combustion.<br /><br />Therefore, the correct reaction that shows the combustion of methane is option a.<br /><br />#
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