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(a) The students investigated reactions to produce magnesium. (i) Magnesium chloride contains magnesium ions and chloride ions. Why does solid magnesium chloride not conduct electricity? (ii) One of the products of the electrolysis of molten magnesium chloride is magnesium. Name the other product. (iii) Why do magnesium ions (mathrm(Mg)_(3)^-) move to the negative electrode? (iv) At the negative electrode, the magnesium ions ( mathrm(Mg)_(3)^- ) gain electrons to become magnesium atoms. (b) The students did the experiment four times and weighed the magnesium produced. The table below shows their results. Experiment & Mass of magnesium produced in grams 1 & 1.13 2 & 0.63 3 & 1.11 4 & 1.09 (i) There is an anomalous result. Suggest one possible reason for the anomalous result. (1) (ii) Calculate the mean mass of magnesium produced, taking account of the anomalous result. Mean mass = qquad qquad (2) (Total 7 marks)

Question

(a) The students investigated reactions to produce magnesium.
(i) Magnesium chloride contains magnesium ions and chloride ions.
Why does solid magnesium chloride not conduct electricity?
(ii) One of the products of the electrolysis of molten magnesium chloride is magnesium. Name the other product.
(iii) Why do magnesium ions (mathrm(Mg)_(3)^-) move to the negative electrode?
(iv) At the negative electrode, the magnesium ions ( mathrm(Mg)_(3)^- ) gain electrons to become magnesium atoms.
(b) The students did the experiment four times and weighed the magnesium produced. The table below shows their results.

 Experiment & Mass of magnesium produced in grams 
 1 & 1.13 
 2 & 0.63 
 3 & 1.11 
 4 & 1.09 


(i) There is an anomalous result. Suggest one possible reason for the anomalous result.
(1)
(ii) Calculate the mean mass of magnesium produced, taking account of the anomalous result.
Mean mass = qquad 
 qquad 
(2)
(Total 7 marks)

(a) The students investigated reactions to produce magnesium. (i) Magnesium chloride contains magnesium ions and chloride ions. Why does solid magnesium chloride not conduct electricity? (ii) One of the products of the electrolysis of molten magnesium chloride is magnesium. Name the other product. (iii) Why do magnesium ions (mathrm(Mg)_(3)^-) move to the negative electrode? (iv) At the negative electrode, the magnesium ions ( mathrm(Mg)_(3)^- ) gain electrons to become magnesium atoms. (b) The students did the experiment four times and weighed the magnesium produced. The table below shows their results. Experiment & Mass of magnesium produced in grams 1 & 1.13 2 & 0.63 3 & 1.11 4 & 1.09 (i) There is an anomalous result. Suggest one possible reason for the anomalous result. (1) (ii) Calculate the mean mass of magnesium produced, taking account of the anomalous result. Mean mass = qquad qquad (2) (Total 7 marks)

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DerekElite · Tutor for 8 years

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i) Solid magnesium chloride does not conduct electricity because its ions are not free to move. <br />ii) Chlorine is the other product produced during electrolysis. <br />iii) Positive magnesium ions (+2) move towards negative electrode. <br />iv) A magnesium ion gains two electron to become a neutral magnesium atom. <br />v) The anomalous result might have been generated by inaccurate experimental conditions or measurements.<br />vi) The mean mass of magnesium produced, discarding the anomalous result, amounts to 1.11g.

Explain

## i) Solid magnesium chloride does not conduct electricity because in a solid state, the ions are held together in a lattice structure and are not free to move. Conduction of electricity requires the free movement of charged particles. Hence in solid form, magnesium chloride can't conduct electricity. <br />## ii) The other product from the electrolysis of molten magnesium chloride is chlorine. Chlorine is produced at the positive electrode or anode.<br />## iii) Magnesium ions move towards the negative electrode because they have a positive charge. Any positive charged ion is called a "cation" which moves towards the "cathode", the negatively charged electrode.<br />## iv) Each magnesium ion (\(\left.\mathrm{Mg}^{* +}\right) \)) gains two electrons to become a magnesium atom. This can be represented by the equation: \( \mathrm{Mg^{2+}} + 2e^- → \mathrm{Mg} \)<br />## v) The anomalous result may have been caused by a number of factors such as inaccurate measurement, contamination of the sample or equipment failure.<br />## vi) To calculate the mean mass of magnesium, we first discount the anomalous result, and then sum the mass from the other three trials and finally divide by three (the number of trials).<br /><br />### **Calculation** <br />Mean mass = \(\frac{(1.13+1.11+1.09)}{3}\) = 1.11 g<br /><br />Please note due to the given anomaly (0.63g) in second measurement trial we have calculated already considered built set formulas leaving that out!
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