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Which chemical is the limiting reactant in the following reaction if 5.0 g Zn are heated with 2.4 g MoO_(3) 3Zn+2MoO_(3)arrow Mo_(2)O_(3)+3ZnO square

Question

Which chemical is the limiting reactant in the following reaction if 5.0 g Zn are heated with 2.4 g MoO_(3)
3Zn+2MoO_(3)arrow Mo_(2)O_(3)+3ZnO
square

Which chemical is the limiting reactant in the following reaction if 5.0 g Zn are heated with 2.4 g MoO_(3) 3Zn+2MoO_(3)arrow Mo_(2)O_(3)+3ZnO square

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AriaProfessional · Tutor for 6 years

Answer

Zn

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## Step 1<br />To find the limiting reactant, we need to first convert the weights of the reactants, Zn and MoO3, to moles. This is done by dividing their weights by their respective molar masses. The molar mass of Zn is 65.38 g/mol and that of MoO3 is 143.94 g/mol.<br /><br />## Step 2<br />The number of moles of Zn can be calculated by dividing the weight of Zn (5.0 g) by its molar mass (65.38 g/mol). This gives approximately 0.0765 moles.<br /><br />## Step 3<br />Similarly, the number of moles of MoO3 can be calculated by dividing the weight of MoO3 (2.4 g) by its molar mass (143.94 g/mol). This gives approximately 0.0167 moles.<br /><br />## Step 4<br />From the balanced chemical equation, we can see that the stoichiometric ratio of Zn to MoO3 is 3:2. This means that for every 3 moles of Zn, we need 2 moles of MoO3 for the reaction to occur.<br /><br />## Step 5<br />Comparing the actual mole ratio of Zn to MoO3 (0.0765:0.0167) with the stoichiometric ratio (3:2), we can see that the actual ratio is less than the stoichiometric ratio. This means that all the Zn will be used up before all the MoO3 is used. Therefore, Zn is the limiting reactant.
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