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4. In humans, having freckles (F) is dominant over not having freckles (f). A man who is homozygous and has freckles marries a woman who is heterozygous. Fill in the information below to determine the probability of their offspring having freckles! Father's genotype F F Mother's genotype Probability of each genotype in the offspring: mathrm(FF)=50 % mathrm(FF)=50 % mathrm(ff)=0 % Probability of each phenotype in the offspring: Freckles = No Freckles =

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4. In humans, having freckles (F) is dominant over not having freckles (f). A man who is homozygous and has freckles marries a woman who is heterozygous. Fill in the information below to determine the probability of their offspring having freckles!
Father's genotype F F 
Mother's genotype
Probability of each genotype in the offspring:
 mathrm(FF)=50 % mathrm(FF)=50 % mathrm(ff)=0 % 
Probability of each phenotype in the offspring:
Freckles = 
No Freckles =

4. In humans, having freckles (F) is dominant over not having freckles (f). A man who is homozygous and has freckles marries a woman who is heterozygous. Fill in the information below to determine the probability of their offspring having freckles! Father's genotype F F Mother's genotype Probability of each genotype in the offspring: mathrm(FF)=50 % mathrm(FF)=50 % mathrm(ff)=0 % Probability of each phenotype in the offspring: Freckles = No Freckles =

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VaughnElite · Tutor for 8 years

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Mother's genotype: Ff<br />Probability of each genotype in the offspring:<br />FF = 50%<br />Ff = 50%<br />ff = 0%<br />Probability of each phenotype in the offspring:<br />Freckles = 100%<br />No Freckles = 0%

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## Step 1<br />In this problem, we are dealing with the principles of genetics, specifically the concept of dominance. Dominance is a relationship between alleles of a gene in which one allele masks the expression of another allele in the organism's phenotype. In this case, the dominant trait is having freckles (represented by the letter 'F'), while the recessive trait is not having freckles (represented by the letter 'f').<br /><br />## Step 2<br />The man in this scenario is homozygous for the freckle trait, which means he has two copies of the same allele. Therefore, his genotype is 'FF'.<br /><br />## Step 3<br />The woman is heterozygous for the freckle trait, which means she has two different alleles of a gene. Therefore, her genotype is 'Ff'.<br /><br />## Step 4<br />When these two individuals mate, their genetic traits are inherited by their offspring. We can use a Punnett square to determine the possible genotypes of their offspring.<br /><br />## Step 5<br />The Punnett square for this cross would look like this:<br /><br />| | F | F |<br />|-------|-------|-------|<br />| F | FF | FF |<br />| f | Ff | Ff |<br /><br />## Step 6<br />From the Punnett square, we can see that each offspring has a 50% chance of being 'FF' and a 50% chance of being 'Ff'.<br /><br />## Step 7<br />According to the principles of dominance, both 'FF' and 'Ff' will display freckles. Therefore, the probability of an offspring having freckles is 100%, and the probability of an offspring not having freckles is 0%.
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