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10. As shown in the dingram of rectangle ABCD below, diagonals overline (AC) and overline (BD) intersect at E. If AE=x+2 and BD=4x-16 then the length of overline (AC)

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10. As shown in the dingram of rectangle ABCD
below, diagonals
overline (AC) and overline (BD) intersect at E.
If AE=x+2 and BD=4x-16 then the length of
overline (AC)

10. As shown in the dingram of rectangle ABCD below, diagonals overline (AC) and overline (BD) intersect at E. If AE=x+2 and BD=4x-16 then the length of overline (AC)

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ClaraVeteran · Tutor for 11 years

Answer

To solve this problem, we will use the properties of a rectangle and the given information.Step 1: Recognize that in a rectangle, the diagonals are congruent.This means that \(AC = BD\).Step 2: Use the given information to express \(AC\) in terms of \(x\).Since \(AE = x + 2\) and \(AC\) is twice the length of \(AE\) (because \(E\) is the midpoint of the diagonal \(AC\) in a rectangle), we can write:\(AC = 2 \times AE\)\(AC = 2 \times (x + 2)\)\(AC = 2x + 4\)Step 3: Use the given information to express \(BD\) in terms of \(x\).We are given that \(BD = 4x - 16\).Step 4: Set the expressions for \(AC\) and \(BD\) equal to each other and solve for \(x\).Since \(AC = BD\), we have:\(2x + 4 = 4x - 16\)Step 5: Solve for \(x\).Subtract \(2x\) from both sides:\(4 = 2x - 16\)Add \(16\) to both sides:\(20 = 2x\)Divide by \(2\) to isolate \(x\):\(x = 10\)Step 6: Find the length of \(AC\) using the value of \(x\).Now that we know \(x = 10\), we can substitute it back into the expression for \(AC\):\(AC = 2x + 4\)\(AC = 2(10) + 4\)\(AC = 20 + 4\)\(AC = 24\)Answer:The length of \(\overline{AC}\) is 24 units.
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