Here is the graph of the function y=2x^2+2x-7 Jse the graph to estimate the solutions to the equation 2x^2+2x-7=0

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Question

Here is the graph of the function y=2x^2+2x-7 Jse the graph to estimate the solutions to the equation 2x^2+2x-7=0

Answer 1

The solutions to the equation are \(x = \frac{-2 + \sqrt{(2)^2 - 4*2*(-7)}}{2*2}\) and \(x = \frac{-2 - \sqrt{(2)^2 - 4*2*(-7)}}{2*2}\).

Answer 2

## Step 1: Identify the type of the equation. The given equation is a quadratic equation. A quadratic equation is of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(x\) is the variable. ## Step 2: Identify the values of \(a\), \(b\), and \(c\) in the given equation. In the equation \(2x^2 + 2x - 7 = 0\), \(a = 2\), \(b = 2\), and \(c = -7\). ## Step 3: Use the quadratic formula to find the solutions to the equation. The quadratic formula is given by: ### \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) ## Step 4: Substitute the values of \(a\), \(b\), and \(c\) into the quadratic formula and solve for \(x\).

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Here is the graph of the function y=2x^2+2x-7 Jse the graph to estimate the solutions to the equation 2x^2+2x-7=0

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