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At the weekend, Finlay plans to make a return journey from his home to the shopping centre. He knows the shopping centre is 26 miles away his car will cover an average of 7 km per gallon of fuel the car has/5 lítres of fuel in its tank. (b) Determine if Finlay will have enough fuel to complete this return journey. 1mile=1.609km 1gallon=4.545litres

Question

At the weekend, Finlay plans to make a return journey from his home to the
shopping centre.
He knows
the shopping centre is 26 miles away
his car will cover an average of 7 km per gallon of fuel
the car has/5 lítres of fuel in its tank.
(b) Determine if Finlay will have enough fuel to complete this return
journey.
1mile=1.609km
1gallon=4.545litres

At the weekend, Finlay plans to make a return journey from his home to the shopping centre. He knows the shopping centre is 26 miles away his car will cover an average of 7 km per gallon of fuel the car has/5 lítres of fuel in its tank. (b) Determine if Finlay will have enough fuel to complete this return journey. 1mile=1.609km 1gallon=4.545litres

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GwawrMaster · Tutor for 5 years

Answer

Finlay's car can travel approximately 73.78 km with the fuel it has, which is less than the total distance of the journey (83.668 km). Therefore, Finlay will not have enough fuel to complete the return journey.

Explain

## Step 1:<br />First, we need to convert the distance of the journey from miles to kilometers. Given that 1 mile is approximately 1.609 km, we multiply the total distance of the journey (which is a return journey, so it's twice the distance to the shopping centre) by this conversion factor.<br /><br />### \(26 \text{ miles} \times 2 \times 1.609 \text{ km/mile} = 83.668 \text{ km}\)<br /><br />## Step 2:<br />Next, we need to calculate how many kilometers Finlay's car can travel with the fuel it has. Given that the car can cover an average of 67 km per gallon of fuel and that 1 gallon is approximately 4.545 litres, we first convert the fuel in the tank from litres to gallons, and then multiply by the car's fuel efficiency.<br /><br />### \(5 \text{ litres} \times \frac{1 \text{ gallon}}{4.545 \text{ litres}} \times 67 \text{ km/gallon} = 73.78 \text{ km}\)<br /><br />## Step 3:<br />Finally, we compare the total distance of the journey with the distance that the car can travel with the fuel it has. If the latter is greater than or equal to the former, then Finlay will have enough fuel to complete the journey.
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