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What mass of sodium chloride is when chlorine gas reacts with 0.29 grams of sodium iodide? The unbalanced equation is given below: Nal(s)+Cl_(2)(g)arrow NaCl(s)+b(g)

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What mass of sodium chloride is when chlorine gas reacts with 0.29
grams of sodium iodide? The unbalanced equation is given below:
Nal(s)+Cl_(2)(g)arrow NaCl(s)+b(g)

What mass of sodium chloride is when chlorine gas reacts with 0.29 grams of sodium iodide? The unbalanced equation is given below: Nal(s)+Cl_(2)(g)arrow NaCl(s)+b(g)

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XavierProfessional · Tutor for 6 years

Answer

1. The number of moles of NaI is \(0.29 \, \text{gm} / 149.89424 \, \text{gm/mol} = 0.00193 \, \text{moles}\).<br />2. The molar mass of NaCl is \(22.989768 \, \text{gm/mol} + 35.45 \, \text{gm/mol} = 58.44 \, \text{gm/mol}\).<br />3. The mass of NaCl produced is \(0.00193 \, \text{moles} * 58.44 \, \text{gm/mol} = 0.113 \, \text{gm}\).<br /><br />Therefore, approximately 0.11 gm of Sodium chloride will be produced.

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## Step 1<br />The first step in solving this problem is to balance the given chemical equation.<br />The unbalanced equation is:<br /><br />\[<br />\mathrm{NaI}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{NaCl}(\mathrm{s})+\mathrm{I}_{2}(\mathrm{g})<br />\]<br /><br />After balancing, the equation becomes:<br /><br />\[<br />\mathrm{NaI}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{NaCl}(\mathrm{s})+\mathrm{I}_{2}(\mathrm{g})<br />\]<br /><br />## Step 2<br />Next, we need to convert the mass of sodium iodide (NaI) into moles. The molar mass of NaI is calculated by adding the atomic masses of sodium (Na, 22.989769 gm/mol) and iodine (I, 126.90447 gm/mol), which equals 149.89424 gm/mol.<br /><br />### <br />\[<br />\text{mole NaI} = \frac{\text{mass NaI}}{\text{molar mass NaI}}<br />\]<br /><br />## Step 3<br />The stoichiometry of the balanced chemical equation shows that one mole of NaI produces one mole of NaCl. Therefore, the number of moles of NaI is equal to the number of moles of NaCl.<br /><br />## Step 4<br />The mass of NaCl produced can be calculated by multiplying the number of moles of NaCl by its molar mass. The molar mass of NaCl is calculated by adding the atomic masses of sodium (Na, 22.989768 gm/mol) and chlorine (Cl, 35.45 gm/mol), which equals 58.44 gm/mol.<br /><br />### <br />\[<br />\text{mass NaCl} = \text{mole NaCl} * \text{molar mass NaCl}<br />\]
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