Home
/
Chemistry
/
1) Calculate the energy released in the reaction between hydrogen and oxygen forming water as shown. H_(2(g))+O_(2(g))arrow H_(2)O_((g)

Question

1) Calculate the energy released in the reaction between hydrogen and oxygen forming water as shown.
H_(2(g))+O_(2(g))arrow H_(2)O_((g)

1) Calculate the energy released in the reaction between hydrogen and oxygen forming water as shown. H_(2(g))+O_(2(g))arrow H_(2)O_((g)

expert verifiedVerification of experts

Answer

4.5260 Voting
avatar
AlexisExpert · Tutor for 3 years

Answer

### The energy released in the reaction is 482 kJ.

Explain

## Step1: Determine the balanced chemical equation<br />### Ensure the chemical equation is balanced. For the given reaction, it is:<br />\[<br />2 \mathrm{H}_2 + \mathrm{O}_2 \rightarrow 2 \mathrm{H}_2 \mathrm{O}<br />\]<br /><br />## Step2: Calculate the energy released by breaking bonds<br />### Identify the bond energies involved. The bond energies can approximate the energy changes:<br />- $\mathrm{H}-\mathrm{H}$ bond energy: 436 kJ/mol<br />- $\mathrm{O}=\mathrm{O}$ bond energy: 498 kJ/mol<br />- $\mathrm{O}-\mathrm{H}$ bond energy: 463 kJ/mol<br /><br />## Step3: Calculate the total energy required to break the bonds in the reactants<br />### For the reactants, we have:<br />\[<br />\text{Energy to break } 2 \ \mathrm{H}_2 \text{ bonds} = 2 \times 436 \ \mathrm{kJ/mol} = 872 \ \mathrm{kJ}<br />\]<br />\[<br />\text{Energy to break } 1 \ \mathrm{O}_2 \text{ bond} = 498 \ \mathrm{kJ/mol}<br />\]<br /><br />## Step4: Calculate the total energy released when forming the product bonds<br />### For the products, we have:<br />\[<br />\text{Energy released in forming } 4 \ \mathrm{O}-\mathrm{H} \text{ bonds} = 4 \times 463 \ \mathrm{kJ/mol} = 1852 \ \mathrm{kJ}<br />\]<br /><br />## Step5: Calculate the net energy change<br />### The net energy change can be found by subtracting the energy required to break bonds from the energy released in forming bonds:<br />\[<br />\Delta E = (1852 \ \mathrm{kJ}) - (872 \ \mathrm{kJ} + 498 \ \mathrm{kJ}) = 1852 \ \mathrm{kJ} - 1370 \ \mathrm{kJ} = 482 \ \mathrm{kJ}<br />\]
Click to rate:

Hot Questions

More x