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Look at the equation showing the splitting of water to give hydrogen and oxygen . Use it to find the energy released by forming bonds in this reaction. You will need some of the bond energies from the table. Enter your answer as a number kJ/mol 2H_(2)Oarrow 2H_(2)+O_(2) Bond Bond energy (kJ/mol) Harrow H 436 O=O 498 H-O 464 C-H 413 C=0 803 Nequiv N 945 N+A 391 243 H-Cl 432

Question

Look at the equation showing the splitting of water to give hydrogen and oxygen . Use it to find the
energy released by forming bonds in this reaction. You will need some of the bond energies from the
table.
Enter your answer as a number
kJ/mol
2H_(2)Oarrow 2H_(2)+O_(2)
Bond	Bond energy (kJ/mol)
Harrow H	436
O=O	498
H-O	464
C-H	413
C=0	803
Nequiv N	945
N+A	391
243
H-Cl	432

Look at the equation showing the splitting of water to give hydrogen and oxygen . Use it to find the energy released by forming bonds in this reaction. You will need some of the bond energies from the table. Enter your answer as a number kJ/mol 2H_(2)Oarrow 2H_(2)+O_(2) Bond Bond energy (kJ/mol) Harrow H 436 O=O 498 H-O 464 C-H 413 C=0 803 Nequiv N 945 N+A 391 243 H-Cl 432

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MatildaVeteran · Tutor for 10 years

Answer

### 486 kJ/mol

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## Step 1: Identify Bonds Broken in Reactants<br />### In the reaction \(2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{H}_{2} + \mathrm{O}_{2}\), each water molecule (\(\mathrm{H}_{2}\mathrm{O}\)) has two \(\mathrm{H}-\mathrm{O}\) bonds. Therefore, for 2 \(\mathrm{H}_{2}\mathrm{O}\) molecules, a total of 4 \(\mathrm{H}-\mathrm{O}\) bonds are broken.<br />## Step 2: Calculate Energy Required to Break Bonds<br />### The bond energy for \(\mathrm{H}-\mathrm{O}\) is 464 kJ/mol. Thus, the total energy required to break 4 \(\mathrm{H}-\mathrm{O}\) bonds is \(4 \times 464 = 1856\) kJ.<br />## Step 3: Identify Bonds Formed in Products<br />### In the products, 2 \(\mathrm{H}_{2}\) molecules are formed, each with one \(\mathrm{H}-\mathrm{H}\) bond, and 1 \(\mathrm{O}_{2}\) molecule is formed with one \(\mathrm{O}=\mathrm{O}\) bond. Therefore, 2 \(\mathrm{H}-\mathrm{H}\) bonds and 1 \(\mathrm{O}=\mathrm{O}\) bond are formed.<br />## Step 4: Calculate Energy Released by Forming Bonds<br />### The bond energy for \(\mathrm{H}-\mathrm{H}\) is 436 kJ/mol, and for \(\mathrm{O}=\mathrm{O}\) is 498 kJ/mol. Thus, the total energy released by forming 2 \(\mathrm{H}-\mathrm{H}\) bonds and 1 \(\mathrm{O}=\mathrm{O}\) bond is \((2 \times 436) + 498 = 872 + 498 = 1370\) kJ.<br />## Step 5: Determine Net Energy Change<br />### The net energy change is the difference between the energy required to break the bonds and the energy released by forming the bonds: \(1856 - 1370 = 486\) kJ.<br /><br />#
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