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4. Practice: Turn off Show equation. Fill in the equations for the positron emission of xenon-118 and manganese-50 in the spaces below. Use the Gizmo to check your answers. {}^1xearrow square +square ^-Mnarrow square +square

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4. Practice: Turn off Show equation. Fill in the equations for the positron emission of xenon-118 and
manganese-50 in the spaces below. Use the Gizmo to check your answers.
{}^1xearrow square +square ^-Mnarrow square +square

4. Practice: Turn off Show equation. Fill in the equations for the positron emission of xenon-118 and manganese-50 in the spaces below. Use the Gizmo to check your answers. {}^1xearrow square +square ^-Mnarrow square +square

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LydiaMaster · Tutor for 5 years

Answer

### ${}^{118}_{54}Xe \rightarrow {}^{118}_{53}I + e^+$<br />### ${}^{50}_{25}Mn \rightarrow {}^{50}_{24}Cr + e^+$

Explain

## Step1: Identify the initial nuclei and the process<br />### Positron emission involves a proton converting into a neutron, releasing a positron ($e^+$) and a neutrino ($\nu$). The atomic number decreases by 1, but the mass number remains the same.<br />## Step2: Determine the resulting nuclei<br />### For xenon-118 (${}^{118}_{54}Xe$), after positron emission, the resulting element will have an atomic number of 53 (iodine), but the mass number remains 118.<br />### For manganese-50 (${}^{50}_{25}Mn$), after positron emission, the resulting element will have an atomic number of 24 (chromium), but the mass number remains 50.<br />## Step3: Write the balanced nuclear equations<br />### The balanced equations for the positron emission of xenon-118 and manganese-50 are:<br />\[ {}^{118}_{54}Xe \rightarrow {}^{118}_{53}I + e^+ \]<br />\[ {}^{50}_{25}Mn \rightarrow {}^{50}_{24}Cr + e^+ \]
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