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Question 2 (2 points) 4) Listen How many grams of carbon dioxide gas are in a 1.0-L balloon at STP? 0.045 g 2.08 22.4 Question 3(2 points)

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Question 2 (2 points)
4) Listen
How many grams of carbon dioxide gas are in a
1.0-L balloon at STP?
0.045 g
2.08
22.4
Question 3(2 points)

Question 2 (2 points) 4) Listen How many grams of carbon dioxide gas are in a 1.0-L balloon at STP? 0.045 g 2.08 22.4 Question 3(2 points)

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ErinMaster · Tutor for 5 years

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The mass of CO2 that would occupy a 1.0 L balloon at STP is 1.96 grams.

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## Step 1:<br />At Standard Temperature and Pressure (STP), 1 mole of any gas occupies 22.4 Liters.<br />### **n = \frac{V}{22.4}**<br />Here, we first need to find out how many moles of CO2 would occupy 1.0L volume at STP. The number of moles (\(n\)) can be calculated by the formula \(n = \frac{V}{22.4}\), where \(V\) is the volume.<br /><br />## Step 2:<br />Substitute the given volume into the formula:<br />### **n = \frac{1.0L}{22.4L/mol} = 0.0446 mol**<br />So, we have 0.0446 moles of CO2.<br /><br />## Step 3:<br />Since we know the molar mass of CO2 (1mol of C = 12.01 g, and 2mol of O = 2*16.00 g = 32.00 g. So the molar mass of CO2 = 12.01 g + 32.00 g = 44.01 g), we can now calculate the mass of these moles of CO2.<br />### **m = n \times \text{Molar mass}**<br /><br />## Step 4:<br />Substitute the number of moles and the molar mass into the formula:<br />### **m = 0.0446 mol \times 44.01 g/mol = 1.96 grams**<br />So, the mass of CO2 that would occupy a 1.0 L balloon at STP is 1.96 grams.<br /><br />#
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