A 1.8 g potato core is submerged in water. When it is removed, its mass is 1.9 g. What is the percentage gain in the potato's mass? Round your answer to the neare st hundredth of a percent.

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A 1.8 g potato core is submerged in water. When it is removed, its mass is 1.9 g. What is the percentage gain in the potato's mass? Round your answer to the neare st hundredth of a percent.

Answer 1

\(5.56\, \%\).

Answer 2

We calculate the percentage gain in mass similarly as to how we calculated the percent change in the example. The initial (old) mass of the potato core is \(1.8 \, \text{g}\) and the final (new) mass after submerging in water is \(1.9 \, \text{g}\). The percentage change is given by the formula: \[\left( \frac{{\text{{new value}} - \text{{old value}}}}{\text{{old value}}} \right) \times 100 \] We substitute our given values into the formula, which gives: \[ \left( \frac{{1.9 \, \text{g} - 1.8 \, \text{g}}}{{1.8 \, \text{g}}} \right) \times 100 =\left( \frac{0.1}{1.8}\right) \times 100 .\] After that, we will find \(0.0555555\times 100 =5.55555 \, \% \). Then, we will round his value to two decimal places: \(5.56\, \%\). This is the percentage gain in the potato's mass after being submerged in water.

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A 1.8 g potato core is submerged in water. When it is removed, its mass is 1.9 g. What is the percentage gain in the potato's mass? Round your answer to the neare st hundredth of a percent.

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