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A runner decreases his velocity from 20m/s to 10m/s in 2.0 s. What was his average acceleration? a 6.3m/s^2 b 8.0m/s^2 C 3.2m/s^2 d -5.0m/s^2

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A runner decreases his velocity from 20m/s to 10m/s in 2.0 s. What was his average acceleration? a 6.3m/s^2 b 8.0m/s^2 C 3.2m/s^2 d -5.0m/s^2

A runner decreases his velocity from 20m/s to 10m/s in 2.0 s. What was his average acceleration? a 6.3m/s^2 b 8.0m/s^2 C 3.2m/s^2 d -5.0m/s^2

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EfaProfessional · Tutor for 6 years

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### d $-5.0 \, \text{m/s}^2$

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## Step1: Identify Initial and Final Velocities<br />### The initial velocity \(v_i\) is \(20 \, \text{m/s}\) and the final velocity \(v_f\) is \(10 \, \text{m/s}\).<br /><br />## Step2: Identify Time Interval<br />### The time interval \(\Delta t\) during which the change in velocity occurs is \(2.0 \, \text{s}\).<br /><br />## Step3: Use the Average Acceleration Formula<br />### The formula for average acceleration \(a\) is given by:<br />\[a = \frac{v_f - v_i}{\Delta t}\]<br /><br />## Step4: Substitute the Values<br />### Substituting the given values into the formula:<br />\[a = \frac{10 \, \text{m/s} - 20 \, \text{m/s}}{2.0 \, \text{s}} = \frac{-10 \, \text{m/s}}{2.0 \, \text{s}} = -5.0 \, \text{m/s}^2\]
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