Question

4) A rocket accelerates from 1,000m/s to 5,000m/s in 2 seconds. What is its acceleration?

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The acceleration of the rocket is \(2,000 \mathrm{~m/s^2}\).

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Acceleration is calculated as the change in velocity divided by the time over which this change occurs. The formula for acceleration (a) is:\[a = \frac{\Delta v}{t}\]where \(\Delta v\) is the change in velocity and \(t\) is the time.For this problem, the initial velocity (\(v_i\)) is \(1,000 \mathrm{~m/s}\), and the final velocity (\(v_f\)) is \(5,000 \mathrm{~m/s}\). The time (\(t\)) is 2 seconds. The change in velocity (\(\Delta v\)) is the final velocity minus the initial velocity:\[\Delta v = v_f - v_i = 5,000 \mathrm{~m/s} - 1,000 \mathrm{~m/s} = 4,000 \mathrm{~m/s}\]Now we can plug these values into the acceleration formula:\[a = \frac{4,000 \mathrm{~m/s}}{2 \mathrm{~s}} = 2,000 \mathrm{~m/s^2}\]

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