The equation below can be used to find the specific heat capacity of a substance. Work out the specific heat capacity of a substance if it takes 5 ,200J of energy to heat 2kg of it from 42^circ C to 47^circ C Enter your answer as a number J/kg^circ C C=(E)/(mtimes Theta )

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The equation below can be used to find the specific heat capacity of a substance. Work out the specific heat capacity of a substance if it takes 5 ,200J of energy to heat 2kg of it from 42^circ C to 47^circ C Enter your answer as a number J/kg^circ C C=(E)/(mtimes Theta )

Answer 1

The formula to calculate the specific heat capacity is given by \( Q = m \cdot c \cdot \Delta T \), where: - \( Q \) is the amount of heat energy used in Joules (J). - \( m \) is the mass of the substance in kilograms (kg). - \( c \) is the specific heat capacity, which we are trying to find. - \( \Delta T \) represents the change in temperature, measured in degrees Celsius (°C) In this particular problem, you are given that: - The energy, \( Q \), used was 5200 Joules (J). - The substance's mass, \( m \), was 2 kg. - The change in temperature, \( \Delta T \), can be determined by subtracting the initial temperature from the final temperature, which is \( 47°C - 42°C = 5 °C \) or 5 Kelvin (K), as Celsius and Kelvin have the same scale. We will rearrange our formula to solve for \( c \) as highlighted in the below step by step: Re-arrange formula: \( c = Q / (m \cdot \Delta T) \) Solve with given values: \( c = 5200 \mathrm{~J} / (2 \mathrm{~kg} \cdot 5 \mathrm{~K}) = 520 \mathrm{~J/kg~K} \) Your calculated answer \( c = 520 \mathrm{~J/kg~K} \)~~ Thus, yes, the specific heat capacity of the substance is \( 520 \mathrm{~J/kg~K} \).

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The equation below can be used to find the specific heat capacity of a substance. Work out the specific heat capacity of a substance if it takes 5 ,200J of energy to heat 2kg of it from 42^circ C to 47^circ C Enter your answer as a number J/kg^circ C C=(E)/(mtimes Theta )

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