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If a falling rock undergoes a Delta v of 112(m)/(s) due to an bar (a) of m/s^2 how long did it fall? a 11.4 seconds b 3.5 seconds C 9.8 seconds d 6.7 seconds

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If a falling rock undergoes a Delta v of 112(m)/(s) due to an bar (a) of m/s^2 how long did it fall? a 11.4 seconds b 3.5 seconds C 9.8 seconds d 6.7 seconds

If a falling rock undergoes a Delta v of 112(m)/(s) due to an bar (a) of m/s^2 how long did it fall? a 11.4 seconds b 3.5 seconds C 9.8 seconds d 6.7 seconds

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RolandMaster · Tutor for 5 years

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### a 11.4 seconds

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## Step1: Identify the given variables<br />### The problem provides the change in velocity, $\Delta v = 112 \frac{m}{s}$, and the average acceleration, $\bar{a} = 9.8 \frac{m}{s^2}$ (assuming standard gravitational acceleration).<br />## Step2: Use the kinematic equation<br />### The kinematic equation relating change in velocity, acceleration, and time is $\Delta v = \bar{a} \cdot t$. We need to solve for $t$.<br />## Step3: Solve for time $t$<br />### Rearrange the equation to solve for $t$: $t = \frac{\Delta v}{\bar{a}}$. Substitute the given values: $t = \frac{112 \frac{m}{s}}{9.8 \frac{m}{s^2}}$.<br />## Step4: Calculate the time<br />### Performing the division gives $t \approx 11.43$ seconds.
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