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When adding and subtracting the answer should have the same number of decimal places as the value with the least number of decimal places (ex.2.3g+2.11g=2.4g) Question 1: 0.0321g+2.24g=? A. 2.39 B. 2.27 C. 2.2729 D. 2.27219 square For numbers written in scientific notation, the same significant figures rules apply as in regular numbers Examples: 1sig.fig.(1times 10^2) 2sig.fig.(1.0times 10^2) 3sig.fig.(1.00times 10^2) 4sig.fg(1.000times 10^3) When multiplying and dividing the answer should have the same number of decimal places as the value with the least number of significant figures (ex. 2.2mtimes 2.00m=4.4m^2) Question 2: 3.15mtimes 2.500m=? E. 8m^2 F. 7.9m^2 7.88m^2 H 7.875m^2 square Question 5: Multiply the values below to the correct number of significant figures: 3.50mtimes 5.500times 10^2m=? 1.9times 10^3m^2 R. 2.0times 10^3m^2 S. 1.93times 10^3m^2 T. 1.925times 10^3m^2 Question 3: Add the values below to the correct number of significant figures: 3.5g+7.25g+2.652g=? I. 139 J. 13.49 K. 13.40 g square L. 13.402 g USE THE DECODER TO 657 THE LOCK CONBINATION

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When adding and subtracting the answer should have the same number of decimal places as the value with the least number of decimal places (ex.2.3g+2.11g=2.4g) Question 1: 0.0321g+2.24g=? A. 2.39 B. 2.27 C. 2.2729 D. 2.27219 square For numbers written in scientific notation, the same significant figures rules apply as in regular numbers Examples: 1sig.fig.(1times 10^2) 2sig.fig.(1.0times 10^2) 3sig.fig.(1.00times 10^2) 4sig.fg(1.000times 10^3) When multiplying and dividing the answer should have the same number of decimal places as the value with the least number of significant figures (ex. 2.2mtimes 2.00m=4.4m^2) Question 2: 3.15mtimes 2.500m=? E. 8m^2 F. 7.9m^2 7.88m^2 H 7.875m^2 square Question 5: Multiply the values below to the correct number of significant figures: 3.50mtimes 5.500times 10^2m=? 1.9times 10^3m^2 R. 2.0times 10^3m^2 S. 1.93times 10^3m^2 T. 1.925times 10^3m^2 Question 3: Add the values below to the correct number of significant figures: 3.5g+7.25g+2.652g=? I. 139 J. 13.49 K. 13.40 g square L. 13.402 g USE THE DECODER TO 657 THE LOCK CONBINATION

When adding and subtracting the answer should have the same number of decimal places as the value with the least number of decimal places (ex.2.3g+2.11g=2.4g) Question 1: 0.0321g+2.24g=? A. 2.39 B. 2.27 C. 2.2729 D. 2.27219 square For numbers written in scientific notation, the same significant figures rules apply as in regular numbers Examples: 1sig.fig.(1times 10^2) 2sig.fig.(1.0times 10^2) 3sig.fig.(1.00times 10^2) 4sig.fg(1.000times 10^3) When multiplying and dividing the answer should have the same number of decimal places as the value with the least number of significant figures (ex. 2.2mtimes 2.00m=4.4m^2) Question 2: 3.15mtimes 2.500m=? E. 8m^2 F. 7.9m^2 7.88m^2 H 7.875m^2 square Question 5: Multiply the values below to the correct number of significant figures: 3.50mtimes 5.500times 10^2m=? 1.9times 10^3m^2 R. 2.0times 10^3m^2 S. 1.93times 10^3m^2 T. 1.925times 10^3m^2 Question 3: Add the values below to the correct number of significant figures: 3.5g+7.25g+2.652g=? I. 139 J. 13.49 K. 13.40 g square L. 13.402 g USE THE DECODER TO 657 THE LOCK CONBINATION

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Let's solve each question step by step and extract the final answer.**Question 1:**\(0.0321 \mathrm{~g}+2.24 \mathrm{~g}=\) ?Step 1: Add the two numbers.\(0.0321 + 2.24 = 2.2721 \mathrm{~g}\)Step 2: Round to the least number of decimal places in the given numbers.The number with the least decimal places is 2.24 g, which has two decimal places.Final Answer: \(2.27 \mathrm{~g}\)So the answer is B. \(2.27 \mathrm{~g}\)**Question 4:**How many significant figures is in the number:\(9.020 \times 10^{1} 9\)Step 1: Identify the number of significant figures.The number 9.020 has four significant figures (the zeros between non-zero digits and at the end after the decimal point are significant).Final Answer: 4 significant figures.So the answer is P. 4**Question 2:**\(3.15 \mathrm{~m} \times 2.500 \mathrm{~m}=\) ?Step 1: Multiply the two numbers.\(3.15 \times 2.500 = 7.875 \mathrm{~m}^{2}\)Step 2: Round to the least number of significant figures in the given numbers.The number with the least significant figures is 3.15 m, which has three significant figures.Final Answer: \(7.88 \mathrm{~m}^{2}\)So the answer is G. \(7.88 \mathrm{~m}^{2}\)**Question 5:**Multiply the values below to the correct number of significant figures:\(3.50 \mathrm{~m} \times 5.500 \times 10^{2} \mathrm{~m}=\) ?Step 1: Multiply the two numbers.\(3.50 \times 5.500 \times 10^{2} = 1925 \mathrm{~m}^{2}\)Step 2: Round to the least number of significant figures in the given numbers.Both numbers have three significant figures.Final Answer: \(1.93 \times 10^{3} \mathrm{~m}^{2}\)So the answer is S. \(1.93 \times 10^{3} \mathrm{~m}^{2}\)**Question 3:**Add the values below to the correct number of significant figures:\(3.5 \mathrm{~g}+7.25 \mathrm{~g}+2.652 \mathrm{~g}=\) ?Step 1: Add the three numbers.\(3.5 + 7.25 + 2.652 = 13.402 \mathrm{~g}\)Step 2: Round to the least number of decimal places in the given numbers.The number with the least decimal places is 3.5 g, which has one decimal place.Final Answer: \(13.4 \mathrm{~g}\)So the answer is K. \(13.40 \mathrm{~g}\)Now, let's use the answers to get the lock combination:Q1: B. \(2.27 \mathrm{~g}\) - The corresponding letter is Q2.Q4: P. 4 - The corresponding letter is Letter 4.Q2: G. \(7.88 \mathrm{~m}^{2}\) - The corresponding letter is Q3.Q5: S. \(1.93 \times 10^{3} \mathrm{~m}^{2}\) - The corresponding letter is Q5.Q3: K. \(13.40 \mathrm{~g}\) - The corresponding letter is Q4.The lock combination, using the corresponding letters, is:Q2, Letter 4, Q3, Q5, Q4.
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