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9. A soccer player kicks a 7 kg ball and it travels at a velocity of 23m/s If the ball was hit with 6 N of force, how long was the player's foot in contact with the ball?

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9. A soccer player kicks a 7 kg ball and it travels at a velocity of 23m/s If the ball was hit with 6 N of
force, how long was the player's foot in contact with the ball?

9. A soccer player kicks a 7 kg ball and it travels at a velocity of 23m/s If the ball was hit with 6 N of force, how long was the player's foot in contact with the ball?

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OliverMaster · Tutor for 5 years

Answer

The player's foot was in contact with the ball for approximately 26.84 seconds.

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The question provides the mass m = 7 kg of the soccer ball, its velocity v = 23 m/s, and the force F = 6 N applied to the ball, and asks for the time t the player's foot was in contact with the ball. This is a direct application of the second law of motion proposed by Isaac Newton, which usually can be expressed in the formula F = ma. However, we need to find the acceleration first. Acceleration is the change in velocity over time, which can be expressed as a = v/t. We can rearrange this formula to solve for time: t = v/a.First, we need to find the acceleration a. We can do this by rearranging the formula F = ma to solve for a: a = F/m. Substituting the given force and mass, that is, F = 6 N and m = 7 kg, we get a = 6/7 = 0.857 m/s².Then, we substitute the found acceleration and the given velocity into the formula t = v/a to find the time. That is, v = 23 m/s and a = 0.857 m/s², we get t = 23/0.857 = 26.84 s.
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