c) Ben adds another identical bulb to the circuit in series. How does the brightness of the first bulb change? __

Question

Question

c) Ben adds another identical bulb to the circuit in series. How does the brightness of the first bulb change? __

Answer 1

The brightness of the first bulb decreases.

Answer 2

## Step 1: In a series circuit, the total resistance of the circuit increases when another component (in this case, an identical bulb) is added. This is because the total resistance in a series circuit is the sum of the individual resistances. ### \(R_{total} = R_1 + R_2 + R_3 + ... + R_n\) ## Step 2: The increase in total resistance leads to a decrease in the total current flowing through the circuit, as per Ohm's law. Ohm's law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. ### \(I = \frac{V}{R}\) ## Step 3: The decrease in current results in a decrease in the brightness of the bulbs. This is because the brightness of a bulb in a circuit is directly proportional to the power dissipated by it, which is given by the product of the current flowing through it and the voltage across it. ### \(P = IV\)

Question

c) Ben adds another identical bulb to the circuit in series. How does the brightness of the first bulb change? __

Answer

Answer

Explain

Hot Questions