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Question 77 of78 Tania's little sister sits 1.2 m from the pivot of a see-saw. Her mass provides a force of 200 N. Tanla pushes down on the other end of the see-saw to make it balance. The maximum pushing force she can provide is 100 N. How far from the pivot must Tania push to make the see-saw balance? Enter your answer as a number m

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Question 77 of78
Tania's little sister sits 1.2 m from the pivot of a see-saw. Her mass provides a force of 200 N. Tanla
pushes down on the other end of the see-saw to make it balance. The maximum pushing force she
can provide is 100 N. How far from the pivot must Tania push to make the see-saw balance?
Enter your answer as a number
m

Question 77 of78 Tania's little sister sits 1.2 m from the pivot of a see-saw. Her mass provides a force of 200 N. Tanla pushes down on the other end of the see-saw to make it balance. The maximum pushing force she can provide is 100 N. How far from the pivot must Tania push to make the see-saw balance? Enter your answer as a number m

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PerynProfessional · Tutor for 6 years

Answer

The distance Tania must push from the pivot to balance the seesaw is 2.4 m.

Explain

The problem relates to the principle of balancing torques and forces. It involves understanding the idea behind moment of force (or just moment), which is a measure of its tendency to cause a body to rotate about a specific point or axis. The principle is rather simple: for a system (in this case, the seesaw) to be balanced or in equilibrium, the sum of the moments on both sides of the pivot must be equal. <br /><br />We are given that Tania's little sister is sitting 1.2 m away from the pivot and is exerting a force of 200 N downwards due to her weight. This means that the moment exerted by the sister is the product of the distance and the force, which is equal to 1.2 m * 200 N = 240 N.m.<br /><br />On the other side, we are told that Tania can push with a maximum force of 100 N. To balance her sister’s force on the seesaw, she needs to exert an equally opposing moment but from a greater distance from the pivot, since the force she can apply is smaller. To calculate this distance (d), we set up the equation as follows:<br /><br />(moment exerted by the sister) = (moment exerted by Tania)<br />=> (force by the sister * distance) = (force by Tania * distance)<br />=> (200 N * 1.2 m) = (100 N * d)<br /><br />Now if we solve this equation for d (distance Tania should push from pivot), <br /><br />=> (d = 200 N * 1.2 m / 100 N),<br /><br />we get
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