Question 6 (1poin) The diagram shows an object with a mass of 1.0 kilogram attached to a string 0.50 meter long.The object is moving of 5.0 meters per second in a horizontal circular path with center at point 0. square What is the magnitude of the centripetal force acting on the object? - ION 2.5N c 25N - 50N

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Question 6 (1poin) The diagram shows an object with a mass of 1.0 kilogram attached to a string 0.50 meter long.The object is moving of 5.0 meters per second in a horizontal circular path with center at point 0. square What is the magnitude of the centripetal force acting on the object? - ION 2.5N c 25N - 50N

Answer 1

To find the magnitude of the centripetal force acting on the object, we can use the formula for centripetal force, which is:\[F_c = \frac{mv^2}{r}\]where:- \(F_c\) is the centripetal force,- \(m\) is the mass of the object,- \(v\) is the velocity of the object, and- \(r\) is the radius of the circular path.Given:- \(m = 1.0\) kg (mass of the object),- \(v = 5.0\) m/s (velocity of the object), and- \(r = 0.50\) m (radius of the circular path).Now, we can plug these values into the formula:\[F_c = \frac{(1.0 \text{ kg})(5.0 \text{ m/s})^2}{0.50 \text{ m}}\]\[F_c = \frac{1.0 \times 25}{0.50}\]\[F_c = \frac{25}{0.50}\]\[F_c = 50 \text{ N}\]Therefore, the magnitude of the centripetal force acting on the object is \(50 \text{ N}\).

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