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Reece is given a lift to school. She leaves the house at 8:30 am and arrives at school at 8:50 am. She uses an app on her phone to calculate her average speed for the journey. Her phone displays 6.8m/s What distance did she travel? Give your answer to 2 significant figures.

Question

Reece is given a lift to school.
She leaves the house at 8:30
am and arrives at school at 8:50 am.
She uses an app on her phone to calculate her average speed for the journey.
Her phone displays 6.8m/s
What distance did she travel?
Give your answer to 2 significant figures.

Reece is given a lift to school. She leaves the house at 8:30 am and arrives at school at 8:50 am. She uses an app on her phone to calculate her average speed for the journey. Her phone displays 6.8m/s What distance did she travel? Give your answer to 2 significant figures.

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Answer

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LoganVeteran · Tutor for 10 years

Answer

After performing the multiplication in step 5, we find that the distance Reece travelled is \(8160\) meters or \(8.16\) kilometers to 2 significant figures.

Explain

## Step 1:<br />First, we need to calculate the total time Reece spent on her journey. She left the house at 8:30 am and arrived at school at 8:50 am. This means she spent 20 minutes on the journey.<br /><br />## Step 2:<br />We need to convert this time from minutes to seconds because the speed given is in meters per second (m/s). We know that 1 minute is equal to 60 seconds. Therefore, 20 minutes is equal to \(20 \times 60 = 1200\) seconds.<br /><br />## Step 3:<br />Now, we can calculate the distance she travelled using the formula for distance which is speed multiplied by time. Her speed was \(6.8 \mathrm{~m/s}\) and the time was 1200 seconds.<br /><br />### The formula for distance is: <br />### \(\textbf{Distance} = \textbf{Speed} \times \textbf{Time} \)<br /><br />## Step 4:<br />Substituting the given values into the formula, we get: <br />### \( \textbf{Distance} = 6.8 \mathrm{~m/s} \times 1200 \mathrm{~s} \)<br /><br />## Step 5:<br />Perform the multiplication to find the distance.
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