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The area of the triangle below is (1)/(48) square inches. What is the length of the base? Express your answer as a fraction in simplest form.

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The area of the triangle below is (1)/(48) square inches. What is the length of the base? Express your answer as a fraction in simplest form.

The area of the triangle below is (1)/(48) square inches. What is the length of the base? Express your answer as a fraction in simplest form.

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TrevorMaster · Tutor for 5 years

Answer

To find the area of a triangle, you use the formula:\[\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\]Given that the area of the triangle is \(\frac{1}{48}\) square inches and the height is \(\frac{1}{6}\) inch, we can plug these values into the formula and solve for the base.Step 1: Set up the equation with the given values.\[\frac{1}{48} = \frac{1}{2} \times \text{base} \times \frac{1}{6}\]Step 2: Multiply both sides of the equation by 2 to eliminate the fraction on the right side.\[2 \times \frac{1}{48} = \text{base} \times \frac{1}{6}\]\[\frac{1}{24} = \text{base} \times \frac{1}{6}\]Step 3: Multiply both sides of the equation by 6 to solve for the base.\[6 \times \frac{1}{24} = \text{base}\]\[\frac{1}{4} = \text{base}\]Therefore, the length of the base of the triangle is \(\frac{1}{4}\) inch.
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