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Question An element with mass 210 grams decays by 8.3% per minute. How much of the element is remaining after 15 minutes, to the nearest 10th of a gram? Answer Attemptiout of 2

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An element with mass 210 grams decays by 8.3%  per minute. How much of the element is remaining after 15
minutes, to the nearest 10th of a gram?
Answer Attemptiout of 2

Question An element with mass 210 grams decays by 8.3% per minute. How much of the element is remaining after 15 minutes, to the nearest 10th of a gram? Answer Attemptiout of 2

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BenjaminMaster · Tutor for 5 years

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### 60.6 grams

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## Step 1: Identify the decay formula<br />### The decay of an element can be modeled using the exponential decay formula: $M(t) = M_0 \cdot e^{kt}$, where $M(t)$ is the mass at time $t$, $M_0$ is the initial mass, $k$ is the decay constant, and $t$ is time.<br /><br />## Step 2: Determine the decay constant<br />### The decay rate is given as 8.3% per minute, which means $k = -0.083$ per minute. This is because $k = \ln(\frac{M(t)}{M_0})/t$ and here $\ln(1 - 0.083) \approx -0.083$.<br /><br />## Step 3: Apply the formula to find the remaining mass after 15 minutes<br />### Using the formula with $M_0 = 210$ grams, $k = -0.083$, and $t = 15$ minutes, we get:<br />$$M(15) = 210 \cdot e^{-0.083 \cdot 15}$$<br /><br />## Step 4: Calculate the exponent<br />### Calculate the exponent value:<br />$$-0.083 \cdot 15 = -1.245$$<br /><br />## Step 5: Compute the remaining mass<br />### Substitute the exponent back into the formula and compute:<br />$$M(15) = 210 \cdot e^{-1.245} \approx 210 \cdot 0.2887 = 60.627 \text{ grams}$$<br /><br />## Step 6: Round the result<br />### Round to the nearest tenth of a gram: $60.6$ grams.
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